Math Proofs

<< Return Home
Credit to Wikipedia

3=0 (MAθ 2011, Open Proofs and Logic)

(1) x2 + (x + 1) = 0 Since x = 0 is not a solution, divide (1) by x.
(2) x + 1 + 1x = 0 Rearranging (2),
(3) x + 1 = -1x Substituting (3) into (1),
(4) x2 -1x = 0 (4) can easily be solved (multiply both sides by x, noting x != 0).
(5) x = 1 Substituting (5) into original equation (1),
(6) 12 + 1 + 1 = 0
(7) 3 = 0.

1=0 (Wikipedia, Calculus)

(1) Let x = 1.
(2) ddx x = ddx 1
(3)       1 = 0.

1=3 (Wikipedia, Precalculus)

Noting eπi = cos(π) + i sin(π) = -1 + 0i = -1,
and e3πi = cos(3π) + i sin(3π) = -1 + 0i = -1,
(1) eπi = e3πi
(2) ln(eπi) = ln(e3πi)
(3) πi = 3πi
(4) 1 = 3.

2π=0 (Wikipedia, Algebra II)

Let x = 2π.
(1) sin(x) = 0 Taking arcsin of both sides,
(2) arcsin( sin(x) ) = arcsin(0)Simplifying,
(3) x = 0 Substituting x=2π,
(4) 2π = 0.

2=1 (Wikipedia, Algebra I)

Let a and b be equal, nonzero quantities.
(1) a = b Multiplying both sides by a,
(2) a2 = ab Subtracing b2 from both sides,
(3) a2 - b2 = ab - b2 Factoring,
(4) (a + b)(a - b) = b(a - b) Dividing both sides by (a - b),
(5) a + b = b Substituting a = b,
(6) b + b = b
(7) 2b = b
(8) 2 = 1.